7x^2+192x-150=0

Solution for 7x^2+192x-150=0 equation:

7x^2+192x-150=0

a = 7; b = 192; c = -150;
Δ = b2-4ac
Δ = 1922-4·7·(-150)
Δ = 41064
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{41064}=\sqrt{4*10266}=\sqrt{4}*\sqrt{10266}=2\sqrt{10266}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(192)-2\sqrt{10266}}{2*7}=\frac{-192-2\sqrt{10266}}{14}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(192)+2\sqrt{10266}}{2*7}=\frac{-192+2\sqrt{10266}}{14}
$